If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-169=0
a = 6; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·6·(-169)
Δ = 4056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4056}=\sqrt{676*6}=\sqrt{676}*\sqrt{6}=26\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26\sqrt{6}}{2*6}=\frac{0-26\sqrt{6}}{12} =-\frac{26\sqrt{6}}{12} =-\frac{13\sqrt{6}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26\sqrt{6}}{2*6}=\frac{0+26\sqrt{6}}{12} =\frac{26\sqrt{6}}{12} =\frac{13\sqrt{6}}{6} $
| 49s+5s-46s-4s+3s=19 | | 3x-17+7x-3=180 | | (y+2)^2=2y2 | | 3x-17-7x-3=180 | | 8(2y+4)-6(3y+7)=3y+9 | | 5+3x=5×-11 | | M=x+13 | | 6x+15=3() | | 7x-3+3x-17x=Y= | | .14x=63 | | 45–3x=2x+5 | | (2x+10)+(x+40)=260 | | 2x^2+5x−4=−1 | | 8v=2(4v-1) | | 92x68= | | 13x-17°=180 | | 2x-5+57+57=180 | | 5(x+2)=11x—8 | | 2x-5+57=180 | | 55z‒3(9z+12)=‒64 | | 5x+3=5(x−2) | | -12=4/3(2x-1 | | -17+6r+16r+17r-19r=12 | | 4x-12+63+45=180 | | 15=x/2-(-10) | | 5x-7=19-x | | -14+g=-2 | | 5t-7=2t+3t-7 | | 40=+5(x+9) | | -6x+8=-6x | | 9+x+3x=-7 | | 2.6(5+0.5x)=-1.2(2x+4) |